Parse / print all elements of a json data column -

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От S.Bob
Тема Parse / print all elements of a json data column -
Дата
Msg-id 1e83d780-ece1-9f27-05f8-5c6db7ce04a8@quadratum-braccas.com
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Ответы Re: Parse / print all elements of a json data column -
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I've setup a logical replication slot in a 9.6 cluster.

I have pulled data with a query like this:

SELECT * FROM pg_logical_slot_get_changes('lr_cdc_slot', NULL, NULL, 
'pretty-print', '1')


I've even staged the returned 'data' column in a table like this:

create table json_test as select data::jsonb from 
pg_logical_slot_get_changes('lr_cdc_slot', null, 
null,'include-timestamp','1');


I want to isolate the various "fields" and "values" of the output json 
string (i.e. the table name, the operation, the columns, etc) However I 
am not having much luck.


Here's some of the queries that do work but none of them give me a full 
breakout of the fields:


select jsonb_each(data) from json_test ;

  (change,"[{""kind"": ""insert"", ""table"": ""lr_test_tab"", ""
schema"": ""lr_test_schema"", ""columnnames"": [""id"", ""compan
y_name"", ""status"", ""active_date""], ""columntypes"": [""inte
ger"", ""character varying(100)"", ""character varying(10)"", ""
timestamp with time zone""], ""columnvalues"": [1, ""Acme CO"",
""B+"", ""2017-12-12 10:14:39.899462-05""]}]")
  (timestamp,"""2019-12-12 10:14:39.901252-05""")
(2 rows)



select jsonb_object_keys(data::jsonb) from json_test ;
  jsonb_object_keys
-------------------
  change
  timestamp
(2 rows)



How can I pull each field and it's value from this (i.e kind = insert, 
table = lr_test_tab, columnnames = ...)?


Thanks in advance




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