Re: SQL syntax

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От Stephan Szabo
Тема Re: SQL syntax
Дата
Msg-id 20020731085358.X17229-100000@megazone23.bigpanda.com
обсуждение исходный текст
Ответ на SQL syntax  ("Mindaugas Riauba" <mind@bi.lt>)
Список pgsql-sql
On Wed, 31 Jul 2002, Mindaugas Riauba wrote:

>
>   I have two similar tables with host and services availability
> data (Nagios). And I want to find out services which are not OK
> in first table and OK in second one. Query I used is:
>
> select c.* from coll_servicestatus as c inner join
> servicestatus as s on (c.service_description=s.service_description
> and c.host_name=s.host_name) where c.service_status != 'OK' and
> s.service_status = 'OK';
>
>   Results are fine. But how to write UPDATE statement if I want
> to set those non-OK states in first table to OK if they are OK
> in the second table?
>
>   Something like:
>
> update coll_servicestatus set service_status = 'OK' from
> coll_servicestatus as c, servicestatus as s where
> c.service_description = s.service_description and c.host_name=s.host_name
> and c.service_status != 'OK' and s.service_status = 'OK';
>
>   updates all rows not only required ones.

There are two joins on coll_servicestatus in the above, the one in the
from and one with the updating table.  You could probably remove the
coll_servicestatus as c, and change references to c to coll_servicestatus
or use a subselect, something like:

update coll_servicestatus set service_status='OK' where
service_status!='OK' and exists (select * from servicestatus as s where
coll_servicestatus.service_description=s.service_description and
coll_servicestatus.host_name=s.host_name and s.service_status='OK');



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