John,
Would you have any clue how to figure out the first saturday of any month -
6 days and the last saturday of that month?
I know that this seems odd but i have to run reports for "Non Standard
Months" and well I am clueless.
At 09:55 PM 8/11/00 -0500, you wrote:
>Try using the function date_part such as:
>
>select date_part('week',now());
>
>"and the days that are in that week" I guess want to answer a question
>such as:
>Given a date, what is first date in that same week, and what is the last
>date in that week. There are a couple of approaches to this. My first was:
>
>select
>to_date(date_part('year',now()),'YYYY')+(7*date_part('week',now()));
>
>and the above +6 to the the last day of the week. Another approach for
>this same question is much simplier (if the question is indeed what you
>are asking)
>
>select now()-date_part('dow',now());
>
>This last select gives the Sunday for the current week. To get the
>Saturday, simply:
>
>select now()-date_part('dow',now())+6;
>
>Of course, replace the now() with whatever contains the date or timestamp.
>
>John McKown
>
> > I'm probably staring right at it. (One of the difficulties with RTFMing, is
> > having too many docs!)
> >
> > Is there anything in the API that produces the week of the year, from 1 to
> > 52 or 53 depending on the week of the year, and the days that are in that
> > week?
> >
> > Many thanks.
> >
> > -dlj.
> >
> >
> >