Re: Cumulative result with increment

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От Steve Crawford
Тема Re: Cumulative result with increment
Дата
Msg-id 4D506E8A.30107@pinpointresearch.com
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Ответ на Cumulative result with increment  (Shawn Tayler <stayler@washoecounty.us>)
Ответы Re: Cumulative result with increment  (Shawn Tayler <stayler@washoecounty.us>)
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On 02/07/2011 01:11 PM, Shawn Tayler wrote:
> Hello,
>
> I am struggling with what is probably a simple problem but I am coming
> up blank.  In the interest of full disclosure I am not a very savy
> programmer by any stretch.
>
> I have a table of data from an external source which contains numbers of
> events per operating group per hour per day, kind of like this:
>
> Group |    events  | duration  | timestamp
>
> The Group, events, and duration (milliseconds) are all integers in char
> format.  Timestamp is as stated.  The records are at 1 hour increments.
> I need to sum the events and duration fields in 8 hour (shifts, mid to
> 8AM, 8AM to 4PM, etc).
>
> Id like the output to be in table format ala:
>
> Group | events  |  duration  |   date    | shift
> ------+---------+------------+-----------+-------
> 100   |  26     |00:00:25.00 |2011-01-01 | Day    
>
> I have a function to convert the duration to an interval already and can
> make one to do the shift labeling.  Its the rest that has me stumped.
>
> Any suggestions or direction?
>
> As always, your help is greatly appreciated.
>

I'm not sure exactly what you want but it sounds like you just want an 
output column that has the shift instead of timestamp. You can then sum 
on that column. Don't know what your shifts are called, but this will 
give you dog-, day- and night-shifts based on your times:

case
when extract(hour from '2011-01-12 1600'::timestamptz)< 8 then 'dog'
when extract(hour from now())< 16 then 'day'
else 'night'
end as shiftname

This can be used for grouping as well as display.

Cheers,
Steve



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