Hi.
Maybe I miss something but I can't use 'AS' with 'DELETE' (7.4.3)
Example:
db=# SELECT * FROM temp1 ;host_id | user_id | raw | uniq
---------+---------+-----+------ 2 | 1 | 125 | 85 2 | 2 | 100 | 50
(2 rows)
And there is temp2 just like temp1.
db=# DELETE FROM temp1 AS t1 WHERE EXISTS (SELECT 1 FROM temp2 AS t2
WHERE t2.host_id = t1.host_id AND t2.user_id = t1.user_id);
ERROR: syntax error at or near "AS" at character 19
but
db=# DELETE FROM temp1 WHERE EXISTS (SELECT 1 FROM temp2 AS t2 WHERE
t2.host_id = temp1.host_id AND t2.user_id = temp1.user_id);
DELETE 1
db=# SELECT * FROM temp1 ;host_id | user_id | raw | uniq
---------+---------+-----+------ 2 | 1 | 125 | 85
(1 row)
It make me supply full name of table...
Another example with UPDATE
db=# UPDATE referer_total AS ref SET ref.raw = ref.raw + u.raw, ref.uniq = ref.uniq + u.uniq FROM temp1 AS u
WHEREu.user_id = ref.user_id AND ref.referer = u.referer;
ERROR: syntax error at or near "AS" at character 22
db=# UPDATE referer_total SET
db-# referer_total.raw = referer_total.raw + u.raw,
db-# referer_total.uniq = referer_total.uniq + u.uniq
db-# FROM temp1 AS u WHERE u.user_id = referer_total.user_id
db-# AND referer_total.referer = u.referer;
ERROR: syntax error at or near "." at character 46
So it make me rename temp1's "raw" to something else ("r"), "uniq"
too; and 'AS' not possible too. And finally, working version:
UPDATE referer_total SET raw = raw + r, uniq = uniq + u
FROM temp1 AS u WHERE
u.user_id = referer_total.user_id AND
referer_total.referer = u.referer;
It looks strange, are there any limitations or something else that
make it not possible to use 'AS' in 'DELETE' and 'UPDATE'? Of course
with described workarounds I can eliminate that problems, but I want
to know is it so in 8.x? Or why, if it right behaviour?
--
engineer