Re: How return a row from a function so it is recognized as such by caller?

Поиск
Список
Период
Сортировка
От Merlin Moncure
Тема Re: How return a row from a function so it is recognized as such by caller?
Дата
Msg-id CAHyXU0yadGU6ODWsEbvSZATodshvbjQsjOME7zTEVDnN0RXzaA@mail.gmail.com
обсуждение исходный текст
Ответ на Re: How return a row from a function so it is recognized as such by caller?  (Kenneth Tilton <ktilton@mcna.net>)
Ответы Re: How return a row from a function so it is recognized as such by caller?  (Kenneth Tilton <ktilton@mcna.net>)
Список pgsql-general
Дерево обсуждения 
On Wed, Mar 28, 2012 at 2:49 PM, Kenneth Tilton <ktilton@mcna.net> wrote:
> Well then I have the other error. With this code:
>
>    execute 'select ' || NEW.warn_time_init || '($1)' into bpa using NEW;

try this:
select * from now_plus_30(NEW) into bpa;

:-D

merlin

В списке pgsql-general по дате отправления:

Предыдущее
От: Kenneth Tilton
Дата:
Сообщение: Re: How return a row from a function so it is recognized as such by caller?
Следующее
От: Kenneth Tilton
Дата:
Сообщение: Re: How return a row from a function so it is recognized as such by caller?