Re: [HACKERS] advanced partition matching algorithm forpartition-wise join

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От Etsuro Fujita
Тема Re: [HACKERS] advanced partition matching algorithm forpartition-wise join
Дата
Msg-id CAPmGK15ZpZ_CTDhAuLjFRAZNA0k0jM2WEej8jOQhabq_ZCVx4Q@mail.gmail.com
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Ответ на Re: [HACKERS] advanced partition matching algorithm forpartition-wise join  (Etsuro Fujita <etsuro.fujita@gmail.com>)
Ответы Re: [HACKERS] advanced partition matching algorithm forpartition-wise join  (Ashutosh Bapat <ashutosh.bapat.oss@gmail.com>)
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On Fri, Feb 7, 2020 at 9:57 PM Etsuro Fujita <etsuro.fujita@gmail.com> wrote:
> On Thu, Feb 6, 2020 at 3:55 AM Mark Dilger <mark.dilger@enterprisedb.com> wrote:
> > The patches apply and pass all tests.  A review of the patch vs. master looks reasonable.

I've merged the patches.  Attached is a new version of the patch.

> > The partition_join.sql test has multiple levels of partitioning, but when your patch extends that test with
“advancedpartition-wise join”, none of the tables for the new section have multiple levels.  I spent a little while
reviewingthe code and inventing multiple level partitioning tests for advanced partition-wise join and did not
encounterany problems.  I don’t care whether you use this particular example, but do you want to have multiple level
partitioningin the new test section? 
>
> Yes, I do.
>
> > CREATE TABLE alpha (a double precision, b double precision) PARTITION BY RANGE (a);
> > CREATE TABLE alpha_neg PARTITION OF alpha FOR VALUES FROM ('-Infinity') TO (0) PARTITION BY RANGE (b);
> > CREATE TABLE alpha_pos PARTITION OF alpha FOR VALUES FROM (0) TO ('Infinity') PARTITION BY RANGE (b);
> > CREATE TABLE alpha_nan PARTITION OF alpha FOR VALUES FROM ('Infinity') TO ('NaN');
> > CREATE TABLE alpha_neg_neg PARTITION OF alpha_neg FOR VALUES FROM ('-Infinity') TO (0);
> > CREATE TABLE alpha_neg_pos PARTITION OF alpha_neg FOR VALUES FROM (0) TO ('Infinity');
> > CREATE TABLE alpha_neg_nan PARTITION OF alpha_neg FOR VALUES FROM ('Infinity') TO ('NaN');
> > CREATE TABLE alpha_pos_neg PARTITION OF alpha_pos FOR VALUES FROM ('-Infinity') TO (0);
> > CREATE TABLE alpha_pos_pos PARTITION OF alpha_pos FOR VALUES FROM (0) TO ('Infinity');
> > CREATE TABLE alpha_pos_nan PARTITION OF alpha_pos FOR VALUES FROM ('Infinity') TO ('NaN');
> > INSERT INTO alpha (a, b)
> >     (SELECT * FROM
> >         (VALUES (-1.0::float8), (0.0::float8), (1.0::float8), ('Infinity'::float8)) a,
> >         (VALUES (-1.0::float8), (0.0::float8), (1.0::float8), ('Infinity'::float8)) b
> >     );
> > ANALYZE alpha;
> > ANALYZE alpha_neg;
> > ANALYZE alpha_pos;
> > ANALYZE alpha_nan;
> > ANALYZE alpha_neg_neg;
> > ANALYZE alpha_neg_pos;
> > ANALYZE alpha_neg_nan;
> > ANALYZE alpha_pos_neg;
> > ANALYZE alpha_pos_pos;
> > ANALYZE alpha_pos_nan;
> > CREATE TABLE beta (a double precision, b double precision) PARTITION BY RANGE (a, b);
> > CREATE TABLE beta_lo PARTITION OF beta FOR VALUES FROM (-5, -5) TO (0, 0);
> > CREATE TABLE beta_me PARTITION OF beta FOR VALUES FROM (0, 0) TO (0, 5);
> > CREATE TABLE beta_hi PARTITION OF beta FOR VALUES FROM (0, 5) TO (5, 5);
> > INSERT INTO beta (a, b)
> >     (SELECT * FROM
> >         (VALUES (-1.0::float8), (0.0::float8), (1.0::float8)) a,
> >         (VALUES (-1.0::float8), (0.0::float8), (1.0::float8)) b
> >     );
> > ANALYZE beta;
> > ANALYZE beta_lo;
> > ANALYZE beta_me;
> > ANALYZE beta_hi;
> > EXPLAIN SELECT * FROM alpha INNER JOIN beta ON (alpha.a = beta.a AND alpha.b = beta.b) WHERE alpha.a = 1 AND beta.b
=1; 
> >                                   QUERY PLAN
> > -------------------------------------------------------------------------------
> >  Nested Loop  (cost=0.00..2.11 rows=1 width=32)
> >    ->  Seq Scan on alpha_pos_pos alpha  (cost=0.00..1.06 rows=1 width=16)
> >          Filter: ((b = '1'::double precision) AND (a = '1'::double precision))
> >    ->  Seq Scan on beta_hi beta  (cost=0.00..1.04 rows=1 width=16)
> >          Filter: ((b = '1'::double precision) AND (a = '1'::double precision))
> > (5 rows)
>
> Hmm, I'm not sure this is a good test case for that, because this
> result would be due to partition pruning applied to each side of the
> join before considering partition-wise join; you could get the same
> result even with enable_partitionwise_join=off.  I think it's
> important that the partition-wise join logic doesn't break this query,
> though.

I think this would be beyond the scope of the patch, so I added
different test cases that I think would be better as ones for
multi-level partitioning.

Thanks!

Best regards,
Etsuro Fujita

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