Re: help on a query

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От CHRIS HOOVER
Тема Re: help on a query
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Msg-id NYe01121-06b74e7b@companiongroup.com
обсуждение исходный текст
Ответ на help on a query  (Michelle Murrain <tech@murrain.net>)
Ответы Re: help on a query  (Achilleus Mantzios <achill@matrix.gatewaynet.com>)
Re: help on a query  (Thomas F.O'Connell <tfo@sitening.com>)
Список pgsql-sql
Just curious, what is wrong with the first way of coding the solution?
------------------( Forwarded letter 1 follows )---------------------
Date: Fri, 8 Oct 2004 08:44:23 +0400
To: Thomas.F.O'Connell[tfo]@sitening.com.comp, mmurrain@dbdes.com.comp
Cc: pgsql-sql@postgresql.org.comp
From: sad@bankir.ru.comp
Sender: pgsql-sql-owner+m19150@postgresql.org.comp
Subject: Re: [SQL] help on a query

On Friday 08 October 2004 07:10, Thomas F.O'Connell wrote:
> A query that should get the job done is:
>
> SELECT registration_id
> FROM registrations r
> WHERE NOT EXISTS (
>     SELECT 1
>     FROM receipts
>     WHERE registration_id = r.registration_id
> );

Don't, PLEASE, don't !!!

drive this way :

SELECT r.registration_idFROM registrations AS r
LEFT OUTER JOIN receipts AS recON rec.registration_id = r.registration_id
WHERE rec.registration_id IS NULL;



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