Re: Counting number of sites with same number of sampling dates

On Wed, 11 Dec 2019, Michael Lewis wrote:

> Put what you have in a subquery and group/aggregate again.
>
> select sample_count, count( site_nbr ) FROM (
> select site_nbr, count(distinct sampdate) AS sample_count from wrb_hg_cong
> group by site_nbr order by site_nbr
> ) sub
> group by sample_count;

Michael,

Well, darn! I totally speced using a subquery. Thank you very much for an
important lesson.

Best regards,

Rich