Hi Scott,
what about using a Common Table Expression and the clause WITH ?
I am not at home now but you can write something like
WITH top5 AS (SELECT vendor_name AS vendor_name, count(DISTINCT inv_id) AS "# of Invoices"
FROM SpendTable
GROUP BY vendor_name
ORDER BY "# of Invoices" DESC LIMIT 5)
SELECT * FROM top5
UNION
SELECT 'all other' AS vendor_name,
count(DISTINCT st.inv_id) AS "# of Invoices"
FROM SpendTable AS st
WHERE st.vendor_name NOT IN (SELECT vendor_name FROM top5)
ORDER BY "# of Invoices" DESC
Best regards,
--
Jean MAURICE
Grenoble - France - Europe
www.j-maurice.fr
www.atoutfox.org
www.aedtf.org
Le 06/06/2022 à 19:22, Scott Holliday a écrit :
@font-face {font-family:"Cambria Math"; panose-1:2 4 5 3 5 4 6 3 2 4;}@font-face {font-family:Calibri; panose-1:2 15 5 2 2 2 4 3 2 4;}p.MsoNormal, li.MsoNormal, div.MsoNormal {margin:0in; font-size:11.0pt; font-family:"Calibri",sans-serif;}.MsoChpDefault {mso-style-type:export-only; font-size:10.0pt;}div.WordSection1 {page:WordSection1;}Hi,
I’m trying to get up-to-speed with PostgreSQL and have a dumb question. I have a basic query to pull the top 5 vendors that have sent me the most bills. I would like to lump all the other vendors into a row named “Other” and get a count of all those bills excluding the top 5. Below is the basic query.
SELECT vendor_name AS vendor_name,
count(DISTINCT inv_id) AS "# of Invoices"
FROM SpendTable
GROUP BY vendor_name
ORDER BY "# of Invoices" DESC
LIMIT 5
Thanks,
Scott
--
J. MAURICE