Обсуждение: Namespace issues

Поиск
Список
Период
Сортировка

Namespace issues

От
Don Y
Дата:
Given a user defined type foo...
I've created several casts to/from foo and built-in types.
I had adopted a naming convention of:
   baz foo_to_baz(foo);
   foo foo_from_baz(baz);

But:

   ...it is recommended that you continue to follow this old
   convention of naming cast implementation functions after
   the target data type. Many users are used to being able to
   cast data types using a function-style notation, that is
   typename(x). This notation is in fact nothing more nor less
   than a call of the cast implementation function; it is not
   specially treated as a cast. If your conversion functions
   are not named to support this convention then you will have
   surprised users. Since PostgreSQL allows overloading of the
   same function name with different argument types, there is no
   difficulty in having multiple conversion functions from
   different types that all use the target type’s name.

This suggests:
   baz baz(foo);
   foo foo(baz);

I don't see how I can do this in my declarations.  E.g.,
if I have
   baz = {int4, text, float8, ...}
then I end up with several (C) functions all named foo()
but each taking a different argument type (baz).  Since
C doesn't support more than a single namespace for functions,
this just won't work.

What am I failing to see, here?

Thanks!
--don

Re: Namespace issues

От
Martijn van Oosterhout
Дата:
On Tue, May 16, 2006 at 10:29:27AM -0700, Don Y wrote:
> Given a user defined type foo...
> I've created several casts to/from foo and built-in types.
> I had adopted a naming convention of:
>   baz foo_to_baz(foo);
>   foo foo_from_baz(baz);
>
> But:

<snip>

> I don't see how I can do this in my declarations.  E.g.,
> if I have
>   baz = {int4, text, float8, ...}
> then I end up with several (C) functions all named foo()
> but each taking a different argument type (baz).  Since
> C doesn't support more than a single namespace for functions,
> this just won't work.
>
> What am I failing to see, here?

That the name of the function in C doesn't have to be the same as the
name of the function in SQL. You can even define many SQL functions
that all refer to the same C function.

So in your C file yo call them:

cast_foo_to_baz()

and in the SQL you declare as just:

baz()

Have a nice day,
--
Martijn van Oosterhout   <kleptog@svana.org>   http://svana.org/kleptog/
> From each according to his ability. To each according to his ability to litigate.

Вложения

Re: Namespace issues

От
Don Y
Дата:
Martijn van Oosterhout wrote:
> On Tue, May 16, 2006 at 10:29:27AM -0700, Don Y wrote:
>> Given a user defined type foo...
>> I've created several casts to/from foo and built-in types.
>> I had adopted a naming convention of:
>>   baz foo_to_baz(foo);
>>   foo foo_from_baz(baz);
>>
>> But:
>
> <snip>
>
>> I don't see how I can do this in my declarations.  E.g.,
>> if I have
>>   baz = {int4, text, float8, ...}
>> then I end up with several (C) functions all named foo()
>> but each taking a different argument type (baz).  Since
>> C doesn't support more than a single namespace for functions,
>> this just won't work.
>>
>> What am I failing to see, here?
>
> That the name of the function in C doesn't have to be the same as the
> name of the function in SQL. You can even define many SQL functions
> that all refer to the same C function.
>
> So in your C file yo call them:
>
> cast_foo_to_baz()
>
> and in the SQL you declare as just:
>
> baz()

But what *binds* my C declaration to the corresponding SQL
"CREATE CAST"?

E.g.,

CREATE FUNCTION foo_from_baz(baz)
RETURNS foo
AS '...'
LANGUAGE 'C' IMMUTABLE STRICT;

yet, to support the foo(baz) syntax, I would then need (?)
to continue with:

CREATE CAST (baz AS foo)
WITH FUNCTION foo(baz);

or, do I use:

CREATE CAST (baz as foo)
WITH FUNCTION foo_from_baz(baz);

but then how does the "foo(baz)" syntax originate?
or, is this a built in "feature" of the interpreter?
(In which case, why all the commentary <snip>ed that
tells me to name my functions in this way?)

--don

Re: Namespace issues

От
Martijn van Oosterhout
Дата:
On Tue, May 16, 2006 at 10:53:10AM -0700, Don Y wrote:
> But what *binds* my C declaration to the corresponding SQL
> "CREATE CAST"?
>
> E.g.,
>
> CREATE FUNCTION foo_from_baz(baz)
> RETURNS foo
> AS '...'
> LANGUAGE 'C' IMMUTABLE STRICT;

Your create functions would look like:

CREATE FUNCTION foo(baz)
RETURNS foo
AS '$libdir/yourlib','cast_foo_from_baz'
LANGUAGE 'C' IMMUTABLE STRICT;

CREATE FUNCTION foo(baz2)
RETURNS foo
AS '$libdir/yourlib','cast_foo_from_baz2'
LANGUAGE 'C' IMMUTABLE STRICT;

> yet, to support the foo(baz) syntax, I would then need (?)
> to continue with:
>
> CREATE CAST (baz AS foo)
> WITH FUNCTION foo(baz);

Indeed, and also:

CREATE CAST (baz2 TO foo)
WITH FUNCTION foo(baz2)

Hope this helps,
--
Martijn van Oosterhout   <kleptog@svana.org>   http://svana.org/kleptog/
> From each according to his ability. To each according to his ability to litigate.

Вложения