Обсуждение: Oracle Analytical Functions
I'm trying to replicate the use of Oracle's 'lag' and 'over partition by' analytical functions in my query. I have a table (all_client_times) such as: client_id, datetime 122, 2007-05-01 12:00:00 122, 2007-05-01 12:01:00 455, 2007-05-01 12:02:00 455, 2007-05-01 12:03:00 455, 2007-05-01 12:08:00 299, 2007-05-01 12:10:00 299, 2007-05-01 12:34:00 and I would like to create a new view that takes the first table and calculates the time difference in minutes between each row so that the result is something like: client_id,datetime, previousTime, difftime 122,2007-05-01 12:01:00, 2007-05-01 12:00:00, 1 455,2007-05-01 12:03:00, 2007-05-01 12:02:00, 1 455,2007-05-01 12:08:00, 2007-05-01 12:03:00, 5 299,2007-05-01 12:34:00, 2007-05-01 12:10:00, 24 In Oracle I can achieve this with: CREATE OR REPLACE VIEW client_time_diffs AS SELECT client_id,datetime, LAG(datetime, 1) OVER (partition by client_id ORDER BY client_id,datetime) AS previoustime from all_client_times; Any idea how I could replicate this in SQL from PG. Would this be an easy thing to do in Pl/pgSQL? If so could anyone give any directions as to where to start? Appreciate the help, Willem
> -----Original Message----- > From: pgsql-general-owner@postgresql.org [mailto:pgsql-general- > owner@postgresql.org] On Behalf Of Willem Buitendyk > Sent: Wednesday, January 30, 2008 1:15 PM > To: pgsql-general@postgresql.org > Subject: [GENERAL] Oracle Analytical Functions > > I'm trying to replicate the use of Oracle's 'lag' and 'over partition > by' analytical functions in my query. I have a table (all_client_times) > such as: > > client_id, datetime > 122, 2007-05-01 12:00:00 > 122, 2007-05-01 12:01:00 > 455, 2007-05-01 12:02:00 > 455, 2007-05-01 12:03:00 > 455, 2007-05-01 12:08:00 > 299, 2007-05-01 12:10:00 > 299, 2007-05-01 12:34:00 > > and I would like to create a new view that takes the first table and > calculates the time difference in minutes between each row so that the > result is something like: > > client_id,datetime, previousTime, difftime > 122,2007-05-01 12:01:00, 2007-05-01 12:00:00, 1 > 455,2007-05-01 12:03:00, 2007-05-01 12:02:00, 1 > 455,2007-05-01 12:08:00, 2007-05-01 12:03:00, 5 > 299,2007-05-01 12:34:00, 2007-05-01 12:10:00, 24 > > In Oracle I can achieve this with: > > CREATE OR REPLACE VIEW client_time_diffs AS SELECT client_id,datetime, > LAG(datetime, 1) OVER (partition by client_id ORDER BY > client_id,datetime) AS previoustime from all_client_times; > > Any idea how I could replicate this in SQL from PG. Would this be an > easy thing to do in Pl/pgSQL? If so could anyone give any directions as > to where to start? You could certainly create a cursor and then just use age() or other time difference extraction method as appropriate: http://www.postgresql.org/docs/8.2/static/sql-declare.html http://www.postgresql.org/docs/8.2/static/functions-datetime.html
> and I would like to create a new view that takes the first table and
> calculates the time difference in minutes between each row so that the
> result is something like:
>
> client_id,datetime, previousTime, difftime
> 122,2007-05-01 12:01:00, 2007-05-01 12:00:00, 1
> 455,2007-05-01 12:03:00, 2007-05-01 12:02:00, 1
> 455,2007-05-01 12:08:00, 2007-05-01 12:03:00, 5
> 299,2007-05-01 12:34:00, 2007-05-01 12:10:00, 24
>
> Any idea how I could replicate this in SQL from PG. Would this be an
> easy thing to do in Pl/pgSQL? If so could anyone give any directions
> as to where to start?
You can create a set-returning function, that cursors over the table,
like this:
CREATE OR REPLACE FUNCTION lagfunc(
OUT client_id INT,
OUT datetime timestamp,
OUT previousTime timestamp,
OUT difftime interval)
RETURNS SETOF RECORD as $$
DECLARE
thisrow RECORD;
last_client_id INT;
last_datetime timestamp;
BEGIN
FOR thisrow IN SELECT * FROM all_client_times ORDER BY client_id,
datetime LOOP
IF thisrow.client_id = last_client_id THEN
client_id := thisrow.datetime;
datetime := thisrow.datetime;
previousTime := last_datetime;
difftime = datetime-previousTime;
RETURN NEXT;
END IF;
last_client_id := thisrow.client_id;
last_datetime := thisrow.datetime;
END LOOP;
RETURN;
END;
$$ LANGUAGE plpgsql;
select * from lagfunc() limit 10;
select * from lagfunc() where client_id = 455;
Here I used an interval, but you get the idea.
How about something like this:
SELECT
client_id
, datetime
, lagged as previoustime
, datetime - lagged difftime
FROM (
SELECT
client_id
,datetime
,(SELECT MAX(datetime)
FROM all_client_times def
WHERE def.client_id = abc.client_id
AND def.datetime < abc.datetime) as lagged
FROM all_client_times abc
)
WHERE lagged is not null
If you have records with no previous data or multiple rows, you'll
need to play with this to get it to work but it should point in the
right direction.
Hope that helps,
LewisC
--- Willem Buitendyk <willem@pcfish.ca> wrote:
> I'm trying to replicate the use of Oracle's 'lag' and 'over
> partition
> by' analytical functions in my query. I have a table
> (all_client_times)
> such as:
>
> client_id, datetime
> 122, 2007-05-01 12:00:00
> 122, 2007-05-01 12:01:00
> 455, 2007-05-01 12:02:00
> 455, 2007-05-01 12:03:00
> 455, 2007-05-01 12:08:00
> 299, 2007-05-01 12:10:00
> 299, 2007-05-01 12:34:00
>
> and I would like to create a new view that takes the first table
> and
> calculates the time difference in minutes between each row so that
> the
> result is something like:
>
> client_id,datetime, previousTime, difftime
> 122,2007-05-01 12:01:00, 2007-05-01 12:00:00, 1
> 455,2007-05-01 12:03:00, 2007-05-01 12:02:00, 1
> 455,2007-05-01 12:08:00, 2007-05-01 12:03:00, 5
> 299,2007-05-01 12:34:00, 2007-05-01 12:10:00, 24
>
> In Oracle I can achieve this with:
>
> CREATE OR REPLACE VIEW client_time_diffs AS SELECT
> client_id,datetime,
> LAG(datetime, 1) OVER (partition by client_id ORDER BY
> client_id,datetime) AS previoustime from all_client_times;
>
> Any idea how I could replicate this in SQL from PG. Would this be
> an
> easy thing to do in Pl/pgSQL? If so could anyone give any
> directions as
> to where to start?
>
> Appreciate the help,
>
> Willem
>
>
> ---------------------------(end of
> broadcast)---------------------------
> TIP 9: In versions below 8.0, the planner will ignore your desire
> to
> choose an index scan if your joining column's datatypes do
> not
> match
>
Lewis R Cunningham
An Expert's Guide to Oracle Technology
http://blogs.ittoolbox.com/oracle/guide/
LewisC's Random Thoughts
http://lewiscsrandomthoughts.blogspot.com/
create table data (
client_id integer,
datetime timestamp not null
);
create index data_client_id on data(client_id);
copy data from STDIN DELIMITER ',';
122,2007-05-01 12:00:00
122,2007-05-01 12:01:00
455,2007-05-01 12:02:00
455,2007-05-01 12:03:00
455,2007-05-01 12:08:00
299,2007-05-01 12:10:00
299,2007-05-01 12:34:00
\.
CREATE OR REPLACE FUNCTION visits (
OUT client_id INTEGER,
OUT datetime_1 TIMESTAMP,
OUT datetime_2 TIMESTAMP,
OUT dur INTERVAL )
RETURNS SETOF RECORD
LANGUAGE plpgsql
AS $_$
DECLARE
rp data%ROWTYPE; -- previous data table record
r data%ROWTYPE; -- data table record, more recent than
rp
BEGIN
rp = (NULL,NULL);
FOR r IN SELECT * FROM data ORDER BY client_id,datetime LOOP
IF rp.client_id = r.client_id THEN
client_id = r.client_id;
datetime_1 = r.datetime;
datetime_2 = rp.datetime;
dur = r.datetime-rp.datetime;
RETURN NEXT;
END IF;
rp = r;
END LOOP;
RETURN;
END;
$_$;
rkh@rkh=> select * from visits() order by client_id,datetime_1;
client_id | datetime_1 | datetime_2 | dur
-----------+---------------------+---------------------+----------
122 | 2007-05-01 12:01:00 | 2007-05-01 12:00:00 | 00:01:00
299 | 2007-05-01 12:34:00 | 2007-05-01 12:10:00 | 00:24:00
455 | 2007-05-01 12:03:00 | 2007-05-01 12:02:00 | 00:01:00
455 | 2007-05-01 12:08:00 | 2007-05-01 12:03:00 | 00:05:00
(4 rows)
-Reece
--
Reece Hart, http://harts.net/reece/, GPG:0x25EC91A0
Вложения
I tried this function but it keeps returning an error such as: ERROR: invalid input syntax for integer: "2007-05-05 00:34:08" SQL state: 22P02 Context: PL/pgSQL function "lagfunc" line 10 at assignment I checked and there are no datetime values in the client_id field anywhere in my table 'all_client_times' I have no idea what is going on here ... Thanks for the code though - it has taught me a lot all ready; such as using, OUT and SETOF Record Willem Adam Rich wrote: >> and I would like to create a new view that takes the first table and >> calculates the time difference in minutes between each row so that the >> result is something like: >> >> client_id,datetime, previousTime, difftime >> 122,2007-05-01 12:01:00, 2007-05-01 12:00:00, 1 >> 455,2007-05-01 12:03:00, 2007-05-01 12:02:00, 1 >> 455,2007-05-01 12:08:00, 2007-05-01 12:03:00, 5 >> 299,2007-05-01 12:34:00, 2007-05-01 12:10:00, 24 >> >> Any idea how I could replicate this in SQL from PG. Would this be an >> easy thing to do in Pl/pgSQL? If so could anyone give any directions >> as to where to start? >> > > You can create a set-returning function, that cursors over the table, > like this: > > > CREATE OR REPLACE FUNCTION lagfunc( > OUT client_id INT, > OUT datetime timestamp, > OUT previousTime timestamp, > OUT difftime interval) > RETURNS SETOF RECORD as $$ > DECLARE > thisrow RECORD; > last_client_id INT; > last_datetime timestamp; > BEGIN > > FOR thisrow IN SELECT * FROM all_client_times ORDER BY client_id, > datetime LOOP > IF thisrow.client_id = last_client_id THEN > client_id := thisrow.datetime; > datetime := thisrow.datetime; > previousTime := last_datetime; > difftime = datetime-previousTime; > RETURN NEXT; > END IF; > last_client_id := thisrow.client_id; > last_datetime := thisrow.datetime; > END LOOP; > > RETURN; > END; > $$ LANGUAGE plpgsql; > > select * from lagfunc() limit 10; > select * from lagfunc() where client_id = 455; > > > Here I used an interval, but you get the idea. > > > > > > ---------------------------(end of broadcast)--------------------------- > TIP 6: explain analyze is your friend > >
Thanks Reece, I got this to work for me. The only problem was with the ORDER BY clause which did not seem to work properly. I took it out and instead used a sorted view for the data table. Cheers, Willem Reece Hart wrote: > create table data ( > client_id integer, > datetime timestamp not null > ); > create index data_client_id on data(client_id); > > copy data from STDIN DELIMITER ','; > 122,2007-05-01 12:00:00 > 122,2007-05-01 12:01:00 > 455,2007-05-01 12:02:00 > 455,2007-05-01 12:03:00 > 455,2007-05-01 12:08:00 > 299,2007-05-01 12:10:00 > 299,2007-05-01 12:34:00 > \. > > CREATE OR REPLACE FUNCTION visits ( > OUT client_id INTEGER, > OUT datetime_1 TIMESTAMP, > OUT datetime_2 TIMESTAMP, > OUT dur INTERVAL ) > RETURNS SETOF RECORD > LANGUAGE plpgsql > AS $_$ > DECLARE > rp data%ROWTYPE; -- previous data table record > r data%ROWTYPE; -- data table record, more recent than > rp > BEGIN > rp = (NULL,NULL); > FOR r IN SELECT * FROM data ORDER BY client_id,datetime LOOP > IF rp.client_id = r.client_id THEN > client_id = r.client_id; > datetime_1 = r.datetime; > datetime_2 = rp.datetime; > dur = r.datetime-rp.datetime; > RETURN NEXT; > END IF; > rp = r; > END LOOP; > RETURN; > END; > $_$; > > > rkh@rkh=> select * from visits() order by client_id,datetime_1; > client_id | datetime_1 | datetime_2 | dur > -----------+---------------------+---------------------+---------- > 122 | 2007-05-01 12:01:00 | 2007-05-01 12:00:00 | 00:01:00 > 299 | 2007-05-01 12:34:00 | 2007-05-01 12:10:00 | 00:24:00 > 455 | 2007-05-01 12:03:00 | 2007-05-01 12:02:00 | 00:01:00 > 455 | 2007-05-01 12:08:00 | 2007-05-01 12:03:00 | 00:05:00 > (4 rows) > > > -Reece > > > ------------------------------------------------------------------------ > > > ---------------------------(end of broadcast)--------------------------- > TIP 2: Don't 'kill -9' the postmaster
Found the error: client_id := thisrow.datetime; should be client_id := thisrow.client_id; All works well now, Thanks very much, Willem Willem Buitendyk wrote: > I tried this function but it keeps returning an error such as: > > ERROR: invalid input syntax for integer: "2007-05-05 00:34:08" > SQL state: 22P02 > Context: PL/pgSQL function "lagfunc" line 10 at assignment > > I checked and there are no datetime values in the client_id field > anywhere in my table 'all_client_times' > > I have no idea what is going on here ... > > Thanks for the code though - it has taught me a lot all ready; such as > using, OUT and SETOF Record > > Willem > > Adam Rich wrote: >>> and I would like to create a new view that takes the first table and >>> calculates the time difference in minutes between each row so that the >>> result is something like: >>> >>> client_id,datetime, previousTime, difftime >>> 122,2007-05-01 12:01:00, 2007-05-01 12:00:00, 1 >>> 455,2007-05-01 12:03:00, 2007-05-01 12:02:00, 1 >>> 455,2007-05-01 12:08:00, 2007-05-01 12:03:00, 5 >>> 299,2007-05-01 12:34:00, 2007-05-01 12:10:00, 24 >>> >>> Any idea how I could replicate this in SQL from PG. Would this be an >>> easy thing to do in Pl/pgSQL? If so could anyone give any directions >>> as to where to start? >>> >> >> You can create a set-returning function, that cursors over the table, >> like this: >> >> >> CREATE OR REPLACE FUNCTION lagfunc( >> OUT client_id INT, OUT datetime timestamp, OUT >> previousTime timestamp, OUT difftime interval) >> RETURNS SETOF RECORD as $$ DECLARE >> thisrow RECORD; >> last_client_id INT; >> last_datetime timestamp; >> BEGIN >> >> FOR thisrow IN SELECT * FROM all_client_times ORDER BY client_id, >> datetime LOOP >> IF thisrow.client_id = last_client_id THEN >> client_id := thisrow.datetime; >> datetime := thisrow.datetime; >> previousTime := last_datetime; >> difftime = datetime-previousTime; >> RETURN NEXT; >> END IF; >> last_client_id := thisrow.client_id; >> last_datetime := thisrow.datetime; >> END LOOP; >> >> RETURN; >> END; >> $$ LANGUAGE plpgsql; >> >> select * from lagfunc() limit 10; >> select * from lagfunc() where client_id = 455; >> >> >> Here I used an interval, but you get the idea. >> >> >> >> >> >> ---------------------------(end of broadcast)--------------------------- >> TIP 6: explain analyze is your friend >> >> > > > ---------------------------(end of broadcast)--------------------------- > TIP 5: don't forget to increase your free space map settings >
> I tried this function but it keeps returning an error such as: > > ERROR: invalid input syntax for integer: "2007-05-05 00:34:08" > SQL state: 22P02 > Context: PL/pgSQL function "lagfunc" line 10 at assignment Whoops, this line: > > client_id := thisrow.datetime; Should be: client_id := thisrow.client_id;
Hi Willem, Il giorno 30/gen/08, alle ore 22:15, Willem Buitendyk ha scritto: > I'm trying to replicate the use of Oracle's 'lag' and 'over > partition by' analytical functions in my query. I have a table > (all_client_times) such as: > > client_id, datetime > 122, 2007-05-01 12:00:00 > 122, 2007-05-01 12:01:00 > 455, 2007-05-01 12:02:00 > 455, 2007-05-01 12:03:00 > 455, 2007-05-01 12:08:00 > 299, 2007-05-01 12:10:00 > 299, 2007-05-01 12:34:00 > > and I would like to create a new view that takes the first table and > calculates the time difference in minutes between each row so that > the result is something like: > > client_id,datetime, previousTime, difftime > 122,2007-05-01 12:01:00, 2007-05-01 12:00:00, 1 > 455,2007-05-01 12:03:00, 2007-05-01 12:02:00, 1 > 455,2007-05-01 12:08:00, 2007-05-01 12:03:00, 5 > 299,2007-05-01 12:34:00, 2007-05-01 12:10:00, 24 I'd create a "previousTime" column and manage it using a trigger. Anyway, it depends on the time-dependancy of the table Then you can perform "temporal" in a much easier way. You could be interested in taking a look at the following link http://www.cs.arizona.edu/~rts/tdbbook.pdf Cheers, e.
> > I'm trying to replicate the use of Oracle's 'lag' and 'over
> > partition by' analytical functions in my query. I have a table
> > (all_client_times) such as:
> > and I would like to create a new view that takes the first table and
> > calculates the time difference in minutes between each row so that
> > the result is something like:
I thought of a another way of doing this. In my tests, it's a little
faster, too.
DROP SEQUENCE if exists seq1;
DROP SEQUENCE if exists seq2;
CREATE TEMPORARY SEQUENCE seq1 CACHE 1000;
CREATE TEMPORARY SEQUENCE seq2 CACHE 1000;
select a.client_id, b.datetime, a.datetime as previousTime, (b.datetime -
a.datetime) as difftime from
(select nextval('seq1') as s, client_id, datetime from all_client_times
order by client_id, datetime OFFSET 0) as a
inner join
(select nextval('seq2') as s, client_id, datetime from all_client_times
order by client_id, datetime OFFSET 0) as b
on a.s=(b.s-1) where a.client_id=b.client_id
Hi Adam,
Il giorno 31/gen/08, alle ore 16:13, Adam Rich ha scritto:
>>> I'm trying to replicate the use of Oracle's 'lag' and 'over
>>> partition by' analytical functions in my query. I have a table
>>> (all_client_times) such as:
>>> and I would like to create a new view that takes the first table and
>>> calculates the time difference in minutes between each row so that
>>> the result is something like:
>
> I thought of a another way of doing this. In my tests, it's a little
> faster, too.
>
> DROP SEQUENCE if exists seq1;
> DROP SEQUENCE if exists seq2;
> CREATE TEMPORARY SEQUENCE seq1 CACHE 1000;
> CREATE TEMPORARY SEQUENCE seq2 CACHE 1000;
>
> select a.client_id, b.datetime, a.datetime as previousTime,
> (b.datetime -
> a.datetime) as difftime from
> (select nextval('seq1') as s, client_id, datetime from
> all_client_times
> order by client_id, datetime OFFSET 0) as a
> inner join
> (select nextval('seq2') as s, client_id, datetime from
> all_client_times
> order by client_id, datetime OFFSET 0) as b
> on a.s=(b.s-1) where a.client_id=b.client_id
very interesting indeed. I guess this strategy is more interesting than
the trigger (or rule) based one when you perform much more inserts on
the table that
the select you proposed above. It sounds strange that the select
proposed
is faster than a (single) select on the same table with an additional
previousTime
column populated via trigger/rule.
Bye,
e.
Hey Adam,
I tried your sequence method this morning on an unsorted table and for
some reason the order by's aren't working. If I create a sorted view
(client_id, datetime) on the 'all_client_times' table and then use that
view with your sequence method all works fine. The strange thing is
that my table which has about 750K rows only ends up returning 658 rows
with your sequence method using the unsorted table. In fact, when I
tried the same thing with the lagfunc() method you wrote earlier on an
unsorted table the same thing occurs - only returning 658 rows instead
of the 750K. Again, all works well with lagfunc() if I use it on a
sorted view and I remove the order by in the function. This is not too
much of a problem as I can use a sorted view first but I don't
understand why this is happening. Perhaps this is a bug?
As well, I am finding that the lagfunc() is consistently faster than the
sequence method.
cheers,
Willem
Adam Rich wrote:
>>> I'm trying to replicate the use of Oracle's 'lag' and 'over
>>> partition by' analytical functions in my query. I have a table
>>> (all_client_times) such as:
>>> and I would like to create a new view that takes the first table and
>>> calculates the time difference in minutes between each row so that
>>> the result is something like:
>>>
>
> I thought of a another way of doing this. In my tests, it's a little
> faster, too.
>
> DROP SEQUENCE if exists seq1;
> DROP SEQUENCE if exists seq2;
> CREATE TEMPORARY SEQUENCE seq1 CACHE 1000;
> CREATE TEMPORARY SEQUENCE seq2 CACHE 1000;
>
> select a.client_id, b.datetime, a.datetime as previousTime, (b.datetime -
> a.datetime) as difftime from
> (select nextval('seq1') as s, client_id, datetime from all_client_times
> order by client_id, datetime OFFSET 0) as a
> inner join
> (select nextval('seq2') as s, client_id, datetime from all_client_times
> order by client_id, datetime OFFSET 0) as b
> on a.s=(b.s-1) where a.client_id=b.client_id
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 1: if posting/reading through Usenet, please send an appropriate
> subscribe-nomail command to majordomo@postgresql.org so that your
> message can get through to the mailing list cleanly
>
>
Hi Willem, > for some reason the order by's aren't working. Could you provide more details? Do you get a specific error message? > only returning 658 rows instead of the 750K. You should not expect the same row count in both source table and result set. Even in your example -- you provided 8 source rows, and 4 result rows. You can determine the correct number of results via "the number of records, related to client_ids having two or more records in all_client_times, minus one". It may be true that you have 750k records but only 658 rows that satisfy this requirement. What do you get for this query? select count(*) from ( select client_id, count(*) as rows from all_client_times group by client_id having count(*) > 1 ) as x Adam
The 'all_client_times' table has 753698 rows. The lagfunc() on the sorted view returns 753576 rows and appears to work exactly as needed. Using the function on an unsorted table returns only 686 rows and is missing a whole lot of data. Running the count query returns 122 - which is correct as the amount of clients that I have. Each client has between 5 - 7K records each. The way I see it is for each client there will be one row, namely, the first in the series, that will not be included in the final results as it would not have a previous time. With that in mind, if I take my table row count as 753698 and minus the amount of clients I have, 122, then I should get the number of results as 753576 which is correct when I use your methods on a sorted table but which is not correct when I use your methods on an unsorted table. willem Adam Rich wrote: > Hi Willem, > > >> for some reason the order by's aren't working. >> > > Could you provide more details? Do you get a specific error message? > > >> only returning 658 rows instead of the 750K. >> > > You should not expect the same row count in both source table and > result set. Even in your example -- you provided 8 source rows, and > 4 result rows. You can determine the correct number of results via > "the number of records, related to client_ids having two or more records > in all_client_times, minus one". It may be true that you have 750k > records but only 658 rows that satisfy this requirement. > > What do you get for this query? > > select count(*) from ( select client_id, count(*) as rows > from all_client_times group by client_id having count(*) > 1 ) as x > > > Adam > > > > >
Ah, ok. I see what's happening. The data is retrieved from the tables,
and the sequence values are added, PRIOR to the order by, so that after
the order by, they are no longer sorted. (The same thing can happen
in Oracle with ROWNUM).
You can go the sorted view route, or just an inline view, like this:
select a.client_id, b.arbnum, a.arbnum as previousarbnum, (b.arbnum -
a.arbnum) as diffarbnum from
(select nextval('seq1') as s, * from (select client_id, arbnum from arb_test
order by client_id, arbnum OFFSET 0) as y OFFSET 0) as a
inner join (select nextval('seq2') as s, * from (select client_id, arbnum
from arb_test order by client_id, arbnum OFFSET 0)as z OFFSET 0) as b
on a.s=(b.s-1) where a.client_id=b.client_id;
> -----Original Message-----
> From: Willem Buitendyk [mailto:willem@pcfish.ca]
> Sent: Thursday, January 31, 2008 2:48 PM
> To: Adam Rich
> Cc: pgsql-general@postgresql.org
> Subject: Re: [GENERAL] Oracle Analytical Functions
>
> Here is a little test example. It seems that the second order by
> condition is not working - in this case datetime.
>
> create table arb_test (
> client_id integer,
> arbnum integer);
>
> insert into arb_test values (2,1);
> insert into arb_test values (2,33);
> insert into arb_test values (2,6);
> insert into arb_test values (2,76);
> insert into arb_test values (2,111);
> insert into arb_test values (2,10);
> insert into arb_test values (2,55);
> insert into arb_test values (7,12);
> insert into arb_test values (7,6);
> insert into arb_test values (7,144);
> insert into arb_test values (7,63);
> insert into arb_test values (7,87);
> insert into arb_test values (7,24);
> insert into arb_test values (7,22);
> insert into arb_test values (1,14);
> insert into arb_test values (1,23);
> insert into arb_test values (1,67);
> insert into arb_test values (1,90);
> insert into arb_test values (1,2);
> insert into arb_test values (1,5);
> insert into arb_test values (5,8);
> insert into arb_test values (5,42);
> insert into arb_test values (5,77);
> insert into arb_test values (5,9);
> insert into arb_test values (5,89);
> insert into arb_test values (5,23);
> insert into arb_test values (5,11);
>
> DROP SEQUENCE if exists seq1;
> DROP SEQUENCE if exists seq2;
> CREATE TEMPORARY SEQUENCE seq1 CACHE 1000;
> CREATE TEMPORARY SEQUENCE seq2 CACHE 1000;
>
> select a.client_id, b.arbnum, a.arbnum as previousarbnum, (b.arbnum -
> a.arbnum) as diffarbnum from
> (select nextval('seq1') as s, client_id, arbnum from arb_test
> order by client_id, arbnum OFFSET 0) as a
> inner join
> (select nextval('seq2') as s, client_id, arbnum from arb_test
> order by client_id, arbnum OFFSET 0) as b
> on a.s=(b.s-1) where a.client_id=b.client_id;
>
> --create or replace view arb_view as select * from arb_test order by
> client_id, arbnum;
>
> Here are the results:
>
> client_id | arbnum | previousarbnum | diffarbnum
> -----------+--------+----------------+------------
> 1 | 23 | 14 | 9
> 1 | 67 | 23 | 44
> 1 | 90 | 67 | 23
> 1 | 2 | 90 | -88
> 1 | 5 | 2 | 3
> 2 | 33 | 1 | 32
> 2 | 6 | 33 | -27
> 2 | 76 | 6 | 70
> 2 | 111 | 76 | 35
> 2 | 10 | 111 | -101
> 2 | 55 | 10 | 45
> 5 | 42 | 8 | 34
> 5 | 77 | 42 | 35
> 5 | 9 | 77 | -68
> 5 | 89 | 9 | 80
> 5 | 23 | 89 | -66
> 5 | 11 | 23 | -12
> 7 | 6 | 12 | -6
> 7 | 144 | 6 | 138
> 7 | 63 | 144 | -81
> 7 | 87 | 63 | 24
> 7 | 24 | 87 | -63
>
> When I used a sorted view:
>
> create or replace view arb_view as select * from arb_test order by
> client_id, arbnum;
>
> and redid it the results are:
>
> client_id | arbnum | previousarbnum | diffarbnum
> -----------+--------+----------------+------------
> 1 | 5 | 2 | 3
> 1 | 14 | 5 | 9
> 1 | 23 | 14 | 9
> 1 | 67 | 23 | 44
> 1 | 90 | 67 | 23
> 2 | 6 | 1 | 5
> 2 | 10 | 6 | 4
> 2 | 33 | 10 | 23
> 2 | 55 | 33 | 22
> 2 | 76 | 55 | 21
> 2 | 111 | 76 | 35
> 5 | 9 | 8 | 1
> 5 | 11 | 9 | 2
> 5 | 23 | 11 | 12
> 5 | 42 | 23 | 19
> 5 | 77 | 42 | 35
> 5 | 89 | 77 | 12
> 7 | 12 | 6 | 6
> 7 | 22 | 12 | 10
> 7 | 24 | 22 | 2
> 7 | 63 | 24 | 39
> 7 | 87 | 63 | 24
> 7 | 144 | 87 | 57
> (23 rows)
>
>
> This works the way it should.
>
> --drop table arb_test;
> --drop view arb_view;
>
> willem
> > The 'all_client_times' table has 753698 rows. The lagfunc() on the
> > sorted view returns 753576 rows and appears to work exactly as
> > needed. Using the function on an unsorted table returns only 686
> rows
> > and is missing a whole lot of data. Running the count query returns
> > 122 - which is correct as the amount of clients that I have. Each
> > client has between 5 - 7K records each.
> >
> > The way I see it is for each client there will be one row, namely,
> the
> > first in the series, that will not be included in the final results
> as
> > it would not have a previous time. With that in mind, if I take my
> > table row count as 753698 and minus the amount of clients I have,
> > 122, then I should get the number of results as 753576 which is
> > correct when I use your methods on a sorted table but which is not
> > correct when I use your methods on an unsorted table.
> >
> > willem
> >
> > Adam Rich wrote:
> >> Hi Willem,
> >>
> >>
> >>> for some reason the order by's aren't working.
> >>>
> >>
> >> Could you provide more details? Do you get a specific error
> message?
> >>
> >>
> >>> only returning 658 rows instead of the 750K.
> >>>
> >>
> >> You should not expect the same row count in both source table and
> >> result set. Even in your example -- you provided 8 source rows, and
> >> 4 result rows. You can determine the correct number of results via
> >> "the number of records, related to client_ids having two or more
> >> records in all_client_times, minus one". It may be true that you
> >> have 750k
> >> records but only 658 rows that satisfy this requirement.
> >>
> >> What do you get for this query?
> >>
> >> select count(*) from ( select client_id, count(*) as rows from
> >> all_client_times group by client_id having count(*) > 1 ) as x
> >>
> >>
> >> Adam
> >>
> >>
> >>
> >>
> >>
> >
> >
> > ---------------------------(end of broadcast)------------------------
> ---
> > TIP 4: Have you searched our list archives?
> >
> > http://archives.postgresql.org/
> >
Here is a little test example. It seems that the second order by
condition is not working - in this case datetime.
create table arb_test (
client_id integer,
arbnum integer);
insert into arb_test values (2,1);
insert into arb_test values (2,33);
insert into arb_test values (2,6);
insert into arb_test values (2,76);
insert into arb_test values (2,111);
insert into arb_test values (2,10);
insert into arb_test values (2,55);
insert into arb_test values (7,12);
insert into arb_test values (7,6);
insert into arb_test values (7,144);
insert into arb_test values (7,63);
insert into arb_test values (7,87);
insert into arb_test values (7,24);
insert into arb_test values (7,22);
insert into arb_test values (1,14);
insert into arb_test values (1,23);
insert into arb_test values (1,67);
insert into arb_test values (1,90);
insert into arb_test values (1,2);
insert into arb_test values (1,5);
insert into arb_test values (5,8);
insert into arb_test values (5,42);
insert into arb_test values (5,77);
insert into arb_test values (5,9);
insert into arb_test values (5,89);
insert into arb_test values (5,23);
insert into arb_test values (5,11);
DROP SEQUENCE if exists seq1;
DROP SEQUENCE if exists seq2;
CREATE TEMPORARY SEQUENCE seq1 CACHE 1000;
CREATE TEMPORARY SEQUENCE seq2 CACHE 1000;
select a.client_id, b.arbnum, a.arbnum as previousarbnum, (b.arbnum -
a.arbnum) as diffarbnum from
(select nextval('seq1') as s, client_id, arbnum from arb_test
order by client_id, arbnum OFFSET 0) as a
inner join
(select nextval('seq2') as s, client_id, arbnum from arb_test
order by client_id, arbnum OFFSET 0) as b
on a.s=(b.s-1) where a.client_id=b.client_id;
--create or replace view arb_view as select * from arb_test order by
client_id, arbnum;
Here are the results:
client_id | arbnum | previousarbnum | diffarbnum
-----------+--------+----------------+------------
1 | 23 | 14 | 9
1 | 67 | 23 | 44
1 | 90 | 67 | 23
1 | 2 | 90 | -88
1 | 5 | 2 | 3
2 | 33 | 1 | 32
2 | 6 | 33 | -27
2 | 76 | 6 | 70
2 | 111 | 76 | 35
2 | 10 | 111 | -101
2 | 55 | 10 | 45
5 | 42 | 8 | 34
5 | 77 | 42 | 35
5 | 9 | 77 | -68
5 | 89 | 9 | 80
5 | 23 | 89 | -66
5 | 11 | 23 | -12
7 | 6 | 12 | -6
7 | 144 | 6 | 138
7 | 63 | 144 | -81
7 | 87 | 63 | 24
7 | 24 | 87 | -63
When I used a sorted view:
create or replace view arb_view as select * from arb_test order by
client_id, arbnum;
and redid it the results are:
client_id | arbnum | previousarbnum | diffarbnum
-----------+--------+----------------+------------
1 | 5 | 2 | 3
1 | 14 | 5 | 9
1 | 23 | 14 | 9
1 | 67 | 23 | 44
1 | 90 | 67 | 23
2 | 6 | 1 | 5
2 | 10 | 6 | 4
2 | 33 | 10 | 23
2 | 55 | 33 | 22
2 | 76 | 55 | 21
2 | 111 | 76 | 35
5 | 9 | 8 | 1
5 | 11 | 9 | 2
5 | 23 | 11 | 12
5 | 42 | 23 | 19
5 | 77 | 42 | 35
5 | 89 | 77 | 12
7 | 12 | 6 | 6
7 | 22 | 12 | 10
7 | 24 | 22 | 2
7 | 63 | 24 | 39
7 | 87 | 63 | 24
7 | 144 | 87 | 57
(23 rows)
This works the way it should.
--drop table arb_test;
--drop view arb_view;
willem
> The 'all_client_times' table has 753698 rows. The lagfunc() on the
> sorted view returns 753576 rows and appears to work exactly as
> needed. Using the function on an unsorted table returns only 686 rows
> and is missing a whole lot of data. Running the count query returns
> 122 - which is correct as the amount of clients that I have. Each
> client has between 5 - 7K records each.
>
> The way I see it is for each client there will be one row, namely, the
> first in the series, that will not be included in the final results as
> it would not have a previous time. With that in mind, if I take my
> table row count as 753698 and minus the amount of clients I have,
> 122, then I should get the number of results as 753576 which is
> correct when I use your methods on a sorted table but which is not
> correct when I use your methods on an unsorted table.
>
> willem
>
> Adam Rich wrote:
>> Hi Willem,
>>
>>
>>> for some reason the order by's aren't working.
>>>
>>
>> Could you provide more details? Do you get a specific error message?
>>
>>
>>> only returning 658 rows instead of the 750K.
>>>
>>
>> You should not expect the same row count in both source table and
>> result set. Even in your example -- you provided 8 source rows, and
>> 4 result rows. You can determine the correct number of results via
>> "the number of records, related to client_ids having two or more
>> records in all_client_times, minus one". It may be true that you
>> have 750k
>> records but only 658 rows that satisfy this requirement.
>>
>> What do you get for this query?
>>
>> select count(*) from ( select client_id, count(*) as rows from
>> all_client_times group by client_id having count(*) > 1 ) as x
>>
>>
>> Adam
>>
>>
>>
>>
>>
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 4: Have you searched our list archives?
>
> http://archives.postgresql.org/
>
On Jan 31, 2008 8:49 AM, Enrico Sirola <enrico.sirola@gmail.com> wrote: > I'd create a "previousTime" column and manage it using a trigger. > Anyway, it depends on the time-dependancy of the table > Then you can perform "temporal" in a much easier way. > You could be interested in taking a look at the following link > > http://www.cs.arizona.edu/~rts/tdbbook.pdf +1 That book provides many sane examples for handling temporal data. Recommended.