Обсуждение: use fopen iso-8859-1 resource
Readers, Objective, to import a csv file into postgresql database. If understood correctly, the manual section 'fopen' (https://www.php.net/manual/en/function.fopen.php)shows that the file has a "known resource" extant name. Please what is the syntax to assign an unknown file name to the 'fopen' function?
On 8/27/21 2:59 PM, ourdiaspora wrote: > Readers, > > Objective, to import a csv file into postgresql database. If understood correctly, the manual section 'fopen' (https://www.php.net/manual/en/function.fopen.php)shows that the file has a "known resource" extant name. > > Please what is the syntax to assign an unknown file name to the 'fopen' function? > Why not use?: https://www.php.net/manual/en/pdo.pgsqlcopyfromfile.php -- Adrian Klaver adrian.klaver@aklaver.com
‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐ On Friday, August 27th, 2021 at 11:10 PM, Adrian Klaver <adrian.klaver@aklaver.com> wrote: > https://www.php.net/manual/en/pdo.pgsqlcopyfromfile.php > " public PDO::pgsqlCopyFromFile( string $table_name, string $filename, " Sorry but do not understand; the line does not explain what to write in the php file. So far have written: " <?php $userfile=file(./ $dbusertemporary = pg_connect("dbname=cpacweb user=cpaca"); $usertemporarydata = pg_copy_from ( resource $dbusertemporary, string $userdata, array $rows, string $delimiter = ',', string $null_as = '\\N' ): array; " The plan is to write an html file for a user to select a csv file to import into a database. The manual suggests that thefile name is already known (e.g. https://www.php.net/manual/en/function.fgetcsv.php) Instead of: " ... fopen("test.csv", "r")) ... " it would _not_ be possible to write, correct?: " ... fopen("", "r"))
On 8/27/21 3:50 PM, ourdiaspora wrote: > > ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐ > > On Friday, August 27th, 2021 at 11:10 PM, Adrian Klaver <adrian.klaver@aklaver.com> wrote: > >> https://www.php.net/manual/en/pdo.pgsqlcopyfromfile.php >> > > " > public PDO::pgsqlCopyFromFile( > string $table_name, > string $filename, > " > > Sorry but do not understand; the line does not explain what to write in the php file. I'm not a PHP programmer, but I'm going to say it is filename as described here: https://www.php.net/manual/en/function.fopen.php " filename If filename is of the form ... " > The plan is to write an html file for a user to select a csv file to import into a database. The manual suggests that thefile name is already known (e.g. https://www.php.net/manual/en/function.fgetcsv.php) You are asking the user to select a file, so there should be some sort of file reference at that point, correct? Same for below. > > Instead of: > " > ... > fopen("test.csv", "r")) > ... > " > > it would _not_ be possible to write, correct?: > " > ... > fopen("", "r")) > > -- Adrian Klaver adrian.klaver@aklaver.com
On 2021-08-28 09:52:45 -0700, Adrian Klaver wrote: > On 8/27/21 3:50 PM, ourdiaspora wrote: > > On Friday, August 27th, 2021 at 11:10 PM, Adrian Klaver <adrian.klaver@aklaver.com> wrote: > > > > > https://www.php.net/manual/en/pdo.pgsqlcopyfromfile.php > > > > > > > " > > public PDO::pgsqlCopyFromFile( > > string $table_name, > > string $filename, > > " > > > > Sorry but do not understand; the line does not explain what to write in the php file. > > I'm not a PHP programmer, but I'm going to say it is filename as described > here: The use of PHP suggests that this is a web application. So most likely the user is supposed to upload the file via an HTML form. I would suggest to the OP to learn how to process file uploads in PHP. Once they've figured that out it will probably be clear what file name to use. hp -- _ | Peter J. Holzer | Story must make more sense than reality. |_|_) | | | | | hjp@hjp.at | -- Charles Stross, "Creative writing __/ | http://www.hjp.at/ | challenge!"
Вложения
On Saturday, August 28th, 2021 at 5:52 PM, Adrian Klaver <adrian.klaver@aklaver.com> wrote: > > You are asking the user to select a file, so there should be some sort > > of file reference at that point, correct? > This is what causes confusion. If a user has a file named 'mydatafile.csv', why does the manual make reference to open 'test.csv'???: https://www.php.net/manual/en/function.fgetcsv.php " ... if (($handle = fopen("test.csv", "r")) !== FALSE) { ... "
On Fri, Aug 27, 2021 at 2:59 PM ourdiaspora <ourdiaspora@protonmail.com> wrote:
Please what is the syntax to assign an unknown file name to the 'fopen' function?
There isn't one as it would make no sense - how is it supposed to open a file if there is no filename provided to open?
You have to set things up yourself so that the content you want to open exists in a file at a known location and then pass that location to the function. In particular, in a web server context, that means taking the request input from the client that represents a file and saving it somewhere first - then opening that saved content. If the user is supplying a suggested file name for the content you can incorporate that. You can also ignore it and just make something up. It doesn't matter (other than concerns about overwriting existing files). But whatever name you choose to give to the newly created file on the server is the one you pass to fopen. The name/location of the file on the client machine is irrelevant - the server cannot even see that machine (or, at least should not care even if it technically can) per the fundamental architectural principle of "client-server" design.
David J.
On 8/28/21 2:55 PM, ourdiaspora wrote: > > On Saturday, August 28th, 2021 at 5:52 PM, Adrian Klaver <adrian.klaver@aklaver.com> wrote: > >> >> You are asking the user to select a file, so there should be some sort >> >> of file reference at that point, correct? >> > > This is what causes confusion. If a user has a file named 'mydatafile.csv', why does the manual make reference to open'test.csv'???: Because that is a 'dummy' file name for the purposes of illustrating what sort of information needs to be provided. Just substitute in whatever file name is actually being fetched in the production code. > > https://www.php.net/manual/en/function.fgetcsv.php > " > ... > if (($handle = fopen("test.csv", "r")) !== FALSE) { > ... > " > > > -- Adrian Klaver adrian.klaver@aklaver.com