Обсуждение: RE: Get COUNT results from two different columns

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RE: Get COUNT results from two different columns

От
"Clive Swan"
Дата:

Greetings,

I have two separate queries that work individually, returning a count from each column.

 

I want to subtract New(COUNT) from Old(Count)

I get an error when trying to run UNION?

 

I would appreciate any pointers.

 

 

-- COUNT NEW SUPPLIER

--

SELECT new_sup,

COUNT(new_sup)

FROM public."Data"

GROUP BY new_sup

 

This returns

Company_D 35

Company_E 30

Company_F 30

 

 

SELECT newld_sup,

COUNT(old_sup)

FROM public."Data"

GROUP BY old_sup

 

This returns

Company_A 1

Company_B 2

Company_D 35

Company_E 30

Company_F 30

 

 

 

SELECT new_sup,  COUNT(new_sup) AS new_sup_count,

old_sup,  COUNT(old_sup) AS old_sup_count

FROM

(

                SELECT

    new_sup,  COUNT(new_sup) AS new_sup_count

    FROM public."Data"

    GROUP BY new_sup

   

    UNION

   

    SELECT

    old_sup,  COUNT(old_sup) AS old_sup_count

    FROM public."Data"

    GROUP BY old_sup

   

    new_sup_count - old_sup_count

                )

GROUP BY new_sup

Re: Get COUNT results from two different columns

От
Ray O'Donnell
Дата:
On 23/09/2021 14:37, Clive Swan wrote:
> Greetings,
> 
> I have two separate queries that work individually, returning a count 
> from each column.
> 
> I want to subtract New(COUNT) from Old(Count)
> 
> I get an error when trying to run UNION?

At a quick guess, you'll need to move the subtraction outside the two 
subqueries - stuff inside either query can't see anything in the other one.

Ray.


-- 
Raymond O'Donnell // Galway // Ireland
ray@rodonnell.ie



RE: Get COUNT results from two different columns

От
SQL Padawan
Дата:
Hi,


> I have two separate queries that work individually, returning a count from each column.

> I would appreciate any pointers.

>     new_sup,  COUNT(new_sup) AS new_sup_count

>     old_sup,  COUNT(old_sup) AS old_sup_count

At least some of your problem is here - in your UNION-ed table, this is one and the same field and therefore cannot
havetwo different names. 


HTH,

SQL Padawan





Re: Get COUNT results from two different columns

От
Marc Olivé
Дата:
Seems to me that's not an UNION, but a JOIN:

SELECT o.old_count - n.new_count, o.old_sup, n.new_sup
FROM (

    SELECT new_sup, COUNT(new_sup)

    FROM public."Data"

    GROUP BY new_sup
) n
JOIN (

    SELECT old_sup, COUNT(old_sup)

    FROM public."Data"

    GROUP BY old_sup

) o ON o.old_sup = n.new_sup -- I'm gessing this is the join condition you want

;


Regards,


El jue, 23 sept 2021 a las 15:37, Clive Swan (<cliveswan@gmail.com>) escribió:

Greetings,

I have two separate queries that work individually, returning a count from each column.

 

I want to subtract New(COUNT) from Old(Count)

I get an error when trying to run UNION?

 

I would appreciate any pointers.

 

 

-- COUNT NEW SUPPLIER

--

SELECT new_sup,

COUNT(new_sup)

FROM public."Data"

GROUP BY new_sup

 

This returns

Company_D 35

Company_E 30

Company_F 30

 

 

SELECT newld_sup,

COUNT(old_sup)

FROM public."Data"

GROUP BY old_sup

 

This returns

Company_A 1

Company_B 2

Company_D 35

Company_E 30

Company_F 30

 

 

 

SELECT new_sup,  COUNT(new_sup) AS new_sup_count,

old_sup,  COUNT(old_sup) AS old_sup_count

FROM

(

                SELECT

    new_sup,  COUNT(new_sup) AS new_sup_count

    FROM public."Data"

    GROUP BY new_sup

   

    UNION

   

    SELECT

    old_sup,  COUNT(old_sup) AS old_sup_count

    FROM public."Data"

    GROUP BY old_sup

   

    new_sup_count - old_sup_count

                )

GROUP BY new_sup

RE: Get COUNT results from two different columns

От
"Clive Swan"
Дата:
Greetings,

Thanks for the message.

The error message that I get is.

ERROR:
subquery in FROM must have an alias
  Hint: For example, FROM (SELECT ...) [AS] foo.
  Position: 100

Trying to make sense of it..

Clive

-----Original Message-----
From: SQL Padawan [mailto:sql_padawan@protonmail.com]
Sent: 23 September 2021 14:50
To: cliveswan@gmail.com
Cc: pgsql-general@lists.postgresql.org
Subject: RE: Get COUNT results from two different columns


Hi,


> I have two separate queries that work individually, returning a count from each column.

> I would appreciate any pointers.

>     new_sup,  COUNT(new_sup) AS new_sup_count

>     old_sup,  COUNT(old_sup) AS old_sup_count

At least some of your problem is here - in your UNION-ed table, this is one and the same field and therefore cannot
havetwo different names. 


HTH,

SQL Padawan





Re: Get COUNT results from two different columns

От
"David G. Johnston"
Дата:
On Thu, Sep 23, 2021 at 6:37 AM Clive Swan <cliveswan@gmail.com> wrote:

Greetings,

I have two separate queries that work individually, returning a count from each column.

 

I want to subtract New(COUNT) from Old(Count)

 

I get an error when trying to run UNION?


While you finally did provide this info, it is important to be upfront about exactly what error you are receiving.

Honestly, it feels odd leveraging UNION to solve this problem, but upon further reflection it does provide a nice solution.

/* an (incomplete) subquery to be substituted into the main query below /*
SELECT id, count(*) AS positive_counts --positive values
UNION ALL
SELECT id, (- count(*)) AS negative_counts --negative of the count

You now have a table where IDs (can) repeat, but at most appear only twice, once with a positive count and once with a negative count.  All you need to do to get your final answer is sum the positive and negative count together for each ID.

SELECT union_subquery.id, sum(union_subquery.counted)

FROM (/*this is a subquery, in the FROM clause */) AS union_subquery (id, counted)

 -- which requires an alias (name), which your query omitted and why you got the error you described.

-- I added column aliases here to emphasize that there are only two output columns
-- the name of the second column is originally taken from the first unioned query
-- (so, positive_counts, the name negative_counts is discarded once the union is complete.
-- But since writing sum(positive_counts) in the main query would be confusing I renamed
-- the column to just "counted" using the alias clause


David J.
 

RE: Get COUNT results from two different columns

От
"Clive Swan"
Дата:

Hi David,

 

Thanks for the advice much appreciated.

It is the first time that I have encountered this requirement, so was a bit lost in the forest..

 

As I only want a single id and value (new – old), would it be more efficient to use a SUBTRACT rather than a UNION functions??

 

The UNION is working now… thanks..

 

 

-- UNION

SELECT union_subquery.new_sup_id, sum(new_count)

 

FROM

(

                SELECT

                new_sup AS new_sup_id, COUNT(new_sup) AS new_count

                FROM public."data"

                GROUP BY new_sup_id

 

                UNION

 

                SELECT old_sup,

                - COUNT(old_sup) AS old_count

                FROM public."data"

                GROUP BY old_sup

)

AS union_subquery (new_sup_id, new_count)

GROUP BY union_subquery.new_sup_id, union_subquery.new_count

 

 

 

From: David G. Johnston [mailto:david.g.johnston@gmail.com]
Sent: 23 September 2021 17:45
To: cliveswan@gmail.com
Cc: pgsql-generallists.postgresql.org
Subject: Re: Get COUNT results from two different columns

 

On Thu, Sep 23, 2021 at 6:37 AM Clive Swan <cliveswan@gmail.com> wrote:

Greetings,

I have two separate queries that work individually, returning a count from each column.

 

I want to subtract New(COUNT) from Old(Count)

 

I get an error when trying to run UNION?

 

While you finally did provide this info, it is important to be upfront about exactly what error you are receiving.

 

Honestly, it feels odd leveraging UNION to solve this problem, but upon further reflection it does provide a nice solution.

 

/* an (incomplete) subquery to be substituted into the main query below /*

SELECT id, count(*) AS positive_counts --positive values

UNION ALL

SELECT id, (- count(*)) AS negative_counts --negative of the count

 

You now have a table where IDs (can) repeat, but at most appear only twice, once with a positive count and once with a negative count.  All you need to do to get your final answer is sum the positive and negative count together for each ID.

 

SELECT union_subquery.id, sum(union_subquery.counted)

 

FROM (/*this is a subquery, in the FROM clause */) AS union_subquery (id, counted)

 

 -- which requires an alias (name), which your query omitted and why you got the error you described.

 

-- I added column aliases here to emphasize that there are only two output columns

-- the name of the second column is originally taken from the first unioned query

-- (so, positive_counts, the name negative_counts is discarded once the union is complete.

-- But since writing sum(positive_counts) in the main query would be confusing I renamed

-- the column to just "counted" using the alias clause

 

 

David J.