Re: [QUESTION] Window function with partition by and order by

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От Ankit Kumar Pandey
Тема Re: [QUESTION] Window function with partition by and order by
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Msg-id 795fdbcd-57ec-0cd2-d7d4-9949848aa2f0@gmail.com
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Ответ на Re: [QUESTION] Window function with partition by and order by  (Samed YILDIRIM <samed@reddoc.net>)
Список pgsql-sql
On 27/11/22 21:53, Samed YILDIRIM wrote:
Hello Ankit,

It is absolutely expected behaviour of a window function with ORDER BY clause. The default frame clause of window definition is RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW. If you add an ORDER BY clause in a window definition, PostgreSQL takes the current row and all rows before it within the partition into calculation. If you don't add, it means all rows within the partition are peers, and PostgreSQL uses all rows for calculation. I'm putting the related part from the documentation and its link below.

The default framing option is RANGE UNBOUNDED PRECEDING, which is the same as RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW; it sets the frame to be all rows from the partition start up through the current row's last peer (a row that the window's ORDER BY clause considers equivalent to the current row; all rows are peers if there is no ORDER BY).
 

Best regards.
Samed YILDIRIM


On Sun, 27 Nov 2022 at 18:08, Ankit Kumar Pandey <itsankitkp@gmail.com> wrote:
Hello,

While looking at aggregates in window function, I found something
unusual and would be glad I could get some clarification.

Consider following table (mytable):

id, name

1, A

1, A

2, B

3, A

1, A


select *, avg(id) over (partition by name, order by id) from mytable;

Output:

id, name, avg

1, A, 1

1, A, 1

1, A, 1

3, A, 1.5

2, B, 2


Question is: Average of id for partition name (A) should be 6/4 = 1.5
for all rows in that partition but this result is seen only at the last
one row in partition (A). Am I missing here something?


Thanks


--
Regards,
Ankit Kumar Pandey



Thanks, this makes sense.
-- 
Regards,
Ankit Kumar Pandey

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