Re: Conditional return of aggregated data

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От Wim Bertels
Тема Re: Conditional return of aggregated data
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Msg-id f3fadfb74818b0f9324a8d03a934d342ec531ef9.camel@ucll.be
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Ответ на Conditional return of aggregated data  (Laura Smith <n5d9xq3ti233xiyif2vp@protonmail.ch>)
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Hallo Laura,

i don't know if i understand your question fully,
but this might be helpfull?: FILTER

SELECT
    count(*) AS unfiltered,
    count(*) FILTER (WHERE i < 5) AS filtered
FROM generate_series(1,10) AS s(i);
 unfiltered | filtered
------------+----------
         10 |        4
(1 row)

https://www.postgresql.org/docs/current/sql-expressions.html

hth,
Wim

Laura Smith schreef op ma 02-12-2019 om 11:10 [+0000]:
> Hi,
> 
> I have some aggregated statistics which are currently being queried
> as follows:
> 
> create view stats_age as
> SELECT a.category,
>        a.statcount,
>        b.a_desc
> FROM reg_aggregated_stats a,regs_select_age b where a.category='age'
> and a.datapoint::smallint=b.a_val order by a.datapoint asc;
> 
> However, as these relate to event registrations, a suggestion has
> been made that the database really should be returning nothing until
> a certain number of registrations has been met (in order to avoid
> privacy infringing inferrence from what should be an otherwise fully
> irreversibly aggregated dataset).
> 
> Now, the queries are wrapped in PL/PGSQL functions anyway, so I could
> make a second call to Postgres to find out sum(statcount) and then
> conditionally return based on that.
> 
> But is there a smarter way to do this out of a single SQL query ?
> 
> My initial idea was something along the lines of :
>  select (select sum(statcount) from stats_residence) as
> aggstat,statcount,short_name_en from stats_residence where
> aggstat>some_number;
> 
> But as I soon discovered that's not valid syntax! Hence ideas welcome
> from those smarter than me.
> 
> Thanks !
> 
> Laura
> 
> 
-- 
mvg,
Wim Bertels
--
Lector
UC Leuven-Limburg
--
My only love sprung from my only hate!
Too early seen unknown, and known too late!
        -- William Shakespeare, "Romeo and Juliet"


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